Create a résumé keyword density checker

Here’s a Python script that acts as a résumé keyword density checker. It will take a résumé text and a list of keywords, then calculate the density (percentage) of each keyword in the résumé.

python
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import re
from collections import Counter

def clean_text(text):
    # Lowercase and remove non-alphanumeric characters (except spaces)
    text = text.lower()
    text = re.sub(r'[^a-z0-9s]', '', text)
    return text

def keyword_density(resume_text, keywords):
    cleaned_text = clean_text(resume_text)
    words = cleaned_text.split()
    total_words = len(words)
    
    word_counts = Counter(words)
    density_results = {}
    
    for keyword in keywords:
        # Support multi-word keywords
        keyword_clean = clean_text(keyword)
        keyword_words = keyword_clean.split()
        
        if len(keyword_words) == 1:
            count = word_counts[keyword_clean]
        else:
            # Count occurrences of multi-word phrase in text
            pattern = r'b' + r's+'.join(keyword_words) + r'b'
            count = len(re.findall(pattern, cleaned_text))
        
        density = (count / total_words) * 100 if total_words > 0 else 0
        density_results[keyword] = {'count': count, 'density': round(density, 2)}
    
    return density_results

# Example usage:
resume = """
Experienced software developer skilled in Python, Java, and cloud technologies. Strong background in developing scalable applications and working with agile teams.
"""

keywords = ['Python', 'Java', 'cloud', 'Agile', 'scalable applications', 'C++']

densities = keyword_density(resume, keywords)
for k, v in densities.items():
    print(f"Keyword: '{k}' - Count: {v['count']}, Density: {v['density']}%")

How it works:

• Converts résumé text and keywords to lowercase and strips punctuation.

• Supports both single-word and multi-word keywords.

• Calculates count and percentage density based on total word count.

If you’d like, I can also build this as a web app or Excel macro. Let me know!