Extract zip files and rename contents

To extract zip files and rename their contents, you can use various methods depending on your environment. Here’s a simple guide for common approaches:

Using Python (with zipfile and os modules)

python
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import zipfile
import os

# Path to the zip file and extraction folder
zip_path = 'example.zip'
extract_to = 'extracted_files'

# Create extraction directory if it doesn't exist
os.makedirs(extract_to, exist_ok=True)

# Extract zip contents
with zipfile.ZipFile(zip_path, 'r') as zip_ref:
    zip_ref.extractall(extract_to)

# Rename files inside the extracted folder
for i, filename in enumerate(os.listdir(extract_to)):
    old_path = os.path.join(extract_to, filename)
    # Example rename pattern: file_1.ext, file_2.ext, ...
    extension = os.path.splitext(filename)[1]
    new_filename = f"file_{i+1}{extension}"
    new_path = os.path.join(extract_to, new_filename)
    os.rename(old_path, new_path)

Using Command Line (Linux/Mac)

1. Extract zip file:

bash
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unzip example.zip -d extracted_files

2. Rename files inside the folder (example renaming all files to file_1.ext, file_2.ext etc.):

bash
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cd extracted_files
count=1
for file in *; do
  ext="${file##*.}"
  mv "$file" "file_$count.$ext"
  ((count++))
done

Using PowerShell (Windows)

powershell
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Expand-Archive -Path 'C:pathtoexample.zip' -DestinationPath 'C:pathtoextracted_files'

$files = Get-ChildItem -Path 'C:pathtoextracted_files'
$count = 1
foreach ($file in $files) {
    $extension = $file.Extension
    $newName = "file_$count$extension"
    Rename-Item -Path $file.FullName -NewName $newName
    $count++
}

Let me know if you want a solution tailored for a specific programming language or environment!